Computer Networks · TEE · mocks
Q1C · ALOHA throughput
TEE mock B · full paper
TEE · 100 attempted marks · solutions for every choice · current syllabus 702AI0C023
TEE practice mock · Q1C. In a Slotted ALOHA system, the offered load is G=0.6. Find normalized throughput, percentage throughput, and the theoretical maximum. [5 mock marks]
Answer
Given
Protocol = Slotted ALOHA; G = 0.6 attempts/frame time.
To find
S, 100S and the maximum possible S.
Formula and why
S=G e^{-G}Select the formula from the protocol name. The exponent is −G because Slotted ALOHA has a T vulnerable period.
Step-by-step solution
Step 1. Calculate the exponent
−1 × 0.6 = -0.6.
Step 2. Evaluate the exponential
e^{-0.6} \approx 0.548811636Step 3. Multiply by G
S = 0.6 × 0.548811636 ≈ 0.329286982 successful frames/frame time.
Step 4. Convert to percentage
0.329286982 × 100 ≈ 32.9287%.
Step 5. State the maximum separately
The maximum is 1/(1e) ≈ 0.367879 = 36.7879%, at G=1.
Final answer: S ≈ 0.329287; percentage ≈ 32.9287%; Smax ≈ 0.367879 at G=1.