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Q4B · Transport-layer mechanism

TEE mock B · full paper

TEE · 100 attempted marks · solutions for every choice · current syllabus 702AI0C023

TEE practice mock · Q4B. Describe UDP in detail with a labelled header diagram. Explain its services and operation. [10 mock marks]

Answer

User Datagram Protocol (UDP) provides connectionless, message-oriented process delivery. One send creates a datagram; message boundaries are retained. UDP has an 8-byte header, carries ports and length, and offers checksum-based corruption detection. It does not itself guarantee delivery, ordering, duplicate suppression, retransmission, flow control or congestion control.

Swipe across the diagram to read its labels ↔
UDP header: each row contains 32 bits
Diagram: UDP header: each row contains 32 bits. Labels: UDP header: each row contains 32 bits | UDP header: each row contains 32 bits | Source port · 16 | Destination port · 16 | Length · 16 | Checksum · 16 | Total 8 bytes. Length = header + UDP payload.
UDP fixed header: four 16-bit fields, eight bytes total.
UDP fieldWidthPurpose
Source port16 bitsSending endpoint; a zero value can indicate no reply port when unused
Destination port16 bitsReceiving application endpoint
Length16 bitsUDP header plus UDP payload; minimum 8 bytes
Checksum16 bitsError detection over UDP and an IP pseudo-header; not retransmission

Operation and services

  1. The application chooses the destination IP/port and supplies a message. UDP adds its header and passes the datagram to IP without a connection handshake.
  2. The receiving UDP layer validates the length/checksum as applicable and uses the destination endpoint to deliver the datagram.
  3. A corrupt or undeliverable datagram may be discarded; UDP does not recover it. Any reliability or rate-control policy must come from the application or a protocol above UDP.
  4. UDP checksum zero can mean checksum omitted in IPv4. IPv6 ordinarily requires the UDP checksum; specialized exceptions are outside this syllabus.