Computer Networks · TEE · papers
Source answer-key corrections that affect exam working
Past papers: questions, marks and full solutions
TEE · Latest papers first; older variants mapped to current syllabus
| Source | Problem | Verified treatment |
|---|---|---|
| Final Q4(a), IPv6 | Scheme prose says four omitted groups although five groups are visible | :: inserts three groups; full address 0000:0015:0000:0000:0000:0001:0012:1213 |
| Re-exam Q2(a), CRC | Scheme gives CRC 100 but once prints transmitted frame 110010111 | CRC is 100 and frame is 110010100; receiver division is zero |
| Re-exam Q6(b), ALOHA | Scheme multiplies offered frames/s by normalized S for the 500 and 250 cases | Successful frames/s = S/T = offered rate × e^(−2G); results approximately 183.94 and 151.63 frames/s |
| Re-exam Q6(c), transport comparison | Scheme implies a universal UDP/TCP/SCTP speed ranking | Explain overhead/features; real performance depends on workload and network |
| Bucket descriptions | Output described as constant regardless of whether data exists | A data queue drains at configured rate only while nonempty; no packets are created |
| Current syllabus Unit 3 | Printed CDMA/CA in the random-access list | Teach standard CSMA/CA and disclose the apparent typo; CDMA is a separate method |
The question paper fixes the question. An inconsistent scheme is not copied into a solved answer. Arithmetic checks and protocol references support the corrections.