# One complete CNN pipeline

Subject: Deep Learning

Exam: TEE

Reader: https://deep-learning-study-room.vercel.app/#tee/read/7/tee-c7-s9

Canonical: https://deep-learning-study-room.vercel.app/read/dl/tee/section/tee-c7-s9/

**Question.** Input 128 × 128 × 3 → convolution 3 × 3, 16 filters, stride 1, no padding → pooling 2 × 2, stride 2 → convolution 3 × 3, 32 filters, stride 1, no padding → pooling 2 × 2, stride 2 → dense 240 → dense 120 → dense 5 with softmax. Find every output shape and trainable parameter count. Assume one bias per receiving filter or dense neuron.

### Given

Input = 128 × 128 × 3.

Conv: 3 × 3,16 filters,stride 1,valid → pool 2,stride 2.

Conv: 3 × 3,32 filters,stride 1,valid → pool 2,stride 2.

Flatten → dense 240 → dense 120 → dense 5.

One bias per learned filter/dense neuron.

### To find

Find every output shape and layer parameter count, then the network total.

### Formula — which one and why

**Complete CNN calculation.** Carry each output shape into the next layer. Convolution changes spatial size and channel count; pooling changes spatial size; flattening converts all activations into dense-layer inputs.

H,W,C = feature-map height, width and channels; K = kernel size; S = stride; P\_pad = padding. One bias is assumed for each learned filter or dense neuron unless specified otherwise.



$$
N_{\mathrm{out}}=\left\lfloor\frac{N+2P_{\mathrm{pad}}-K}{S}\right\rfloor+1
$$





$$
P_{\mathrm{conv}}=(K^2C_{\mathrm{in}}+1)C_{\mathrm{out}}
$$





$$
n_{\mathrm{flat}}=HWC
$$





$$
P_{\mathrm{dense}}=(n_{\mathrm{in}}+1)n_{\mathrm{out}}
$$





$$
P_{\mathrm{pool}}=P_{\mathrm{flatten}}=0
$$



**Yaad rakhne ka cue:** Ek layer ka output, next layer ka input; shape aur parameters alag count.

### Solution — step by step

**Step 1. Conv 1 size.** (128 − 3)/1 + 1 = 126; output 126 × 126 × 16. Parameters = (3 × 3 × 3 + 1) × 16 = 448.

![Follow all eight layers from the question. Each row keeps the output shape separate from its learned-parameter count.](https://deep-learning-study-room.vercel.app/assets/figures/v_cnn_pipeline.svg)

Diagram: Follow all eight layers from the question. Each row keeps the output shape separate from its learned-parameter count.. Labels: Follow the complete CNN question, one layer at a time | Follow the complete CNN question, one layer at a time | Start with 128 × 128 × 3. Shape and learned-parameter count are separate. | LAYER | OUTPUT SHAPE / LENGTH | PARAMETERS | 1. Convolution 1 | 126 × 126 × 16 | 448 | 2. Pooling 1 | 63 × 63 × 16 | 0 | 3. Convolution 2 | 61 × 61 × 32 | 4,640 | 4. Pooling 2 | 30 × 30 × 32 | 0 | 5. Flatten | 28,800 | 0 | 6. Dense 240 | 240 | 6,912,240 | 7. Dense 120 | 120 | 28,920 | 8. Classifier | 5 | 605 | Total learned parameters = 6,946,853 | Each output is the next layer’s input. Pooling and flattening add no learned | parameters.

Follow all eight layers from the question. Each row keeps the output shape separate from its learned-parameter count. Tap the diagram to enlarge.

**Step 2. Pool 1 size.**  $\left\lfloor\frac{126 - 2}{2}\right\rfloor+1$  = 63; output 63 × 63 × 16. Parameters = 0.

**Step 3. Conv 2 size.** (63 − 3)/1 + 1 = 61; output 61 × 61 × 32. Input channels are now 16, not the original 3. Parameters = (3 × 3 × 16 + 1) × 32 = 4,640.

**Step 4. Pool 2 size.**  $\left\lfloor\frac{61 - 2}{2}\right\rfloor+1$  =  $\left\lfloor 29.5\right\rfloor$  + 1 = 30; output 30 × 30 × 32. Parameters = 0.

**Step 5. Flatten.** 30 × 30 × 32 = 28,800 values. Parameters = 0.

**Step 6. Dense 240.** 28,800 weights per neuron plus one bias, multiplied by 240: (28,800 + 1) × 240 = 6,912,240.

**Step 7. Dense 120.** (240 + 1) × 120 = 28,920.

**Step 8. Classifier.** (120 + 1) × 5 = 605. Softmax itself adds no extra parameters; these 605 belong to the dense class-score layer.

**Step 9. Total.** 448 + 4,640 + 6,912,240 + 28,920 + 605 = **6,946,853**. Most parameters come from the first dense layer.