Intelligent Systems II · TEE · papers
Q1(c) Fuzzy set operations [5]
Final examination · 24 Nov 2025
Actual TEE paper · 100 marks · 3 hours · Q1 compulsory + any 4 of Q2–Q7 · every answer verified (key errors flagged)
Question. Consider two fuzzy sets X = {(c1, 0.6), (c2, 0.8), (c3, 0.3), (c4, 0.5), (c5, 0.7)} and Y = {(c1, 0.4), (c2, 0.5), (c3, 0.9), (c4, 0.6), (c5, 0.2)}. Find 1) X ∪ Y 2) X ∩ Y 3) ¬X ∪ ¬Y 4) ¬X ∩ ¬Y. [5 marks]
Answer
Given
The aligned X and Y memberships printed in this question.
To find
The four requested membership lists in the original element order.
Formula and why it applies
Use max for OR, min for AND, and 1−μ for NOT.
\mu_{X\cup Y}=\max(\mu_X,\mu_Y),\quad\mu_{X\cap Y}=\min(\mu_X,\mu_Y)Solution
Step 1. Complements
¬X = {0.4, 0.2, 0.7, 0.5, 0.3}; ¬Y = {0.6, 0.5, 0.1, 0.4, 0.8}.
Step 2. Table
| c1 | c2 | c3 | c4 | c5 | |
|---|---|---|---|---|---|
| X | 0.6 | 0.8 | 0.3 | 0.5 | 0.7 |
| Y | 0.4 | 0.5 | 0.9 | 0.6 | 0.2 |
| X ∪ Y = max | 0.6 | 0.8 | 0.9 | 0.6 | 0.7 |
| X ∩ Y = min | 0.4 | 0.5 | 0.3 | 0.5 | 0.2 |
| ¬X ∪ ¬Y | 0.6 | 0.5 | 0.7 | 0.5 | 0.8 |
| ¬X ∩ ¬Y | 0.4 | 0.2 | 0.1 | 0.4 | 0.3 |
Step 3. Check with De Morgan's law
¬X ∪ ¬Y must equal 1 − (X ∩ Y) = {0.6, 0.5, 0.7, 0.5, 0.8} ✓, and ¬X ∩ ¬Y must equal 1 − (X ∪ Y) = {0.4, 0.2, 0.1, 0.4, 0.3} ✓.
Official marking: 1 + 1 + 1.5 + 1.5.
Calculate every element separately
Element c1
\neg X:1-0.6=0.4\qquad\neg Y:1-0.4=0.6X\cup Y:\max(0.6,0.4)=0.6X\cap Y:\min(0.6,0.4)=0.4\neg X\cup\neg Y:\max(0.4,0.6)=0.6\neg X\cap\neg Y:\min(0.4,0.6)=0.4Element c2
\neg X:1-0.8=0.2\qquad\neg Y:1-0.5=0.5X\cup Y:\max(0.8,0.5)=0.8X\cap Y:\min(0.8,0.5)=0.5\neg X\cup\neg Y:\max(0.2,0.5)=0.5\neg X\cap\neg Y:\min(0.2,0.5)=0.2Element c3
\neg X:1-0.3=0.7\qquad\neg Y:1-0.9=0.1X\cup Y:\max(0.3,0.9)=0.9X\cap Y:\min(0.3,0.9)=0.3\neg X\cup\neg Y:\max(0.7,0.1)=0.7\neg X\cap\neg Y:\min(0.7,0.1)=0.1Element c4
\neg X:1-0.5=0.5\qquad\neg Y:1-0.6=0.4X\cup Y:\max(0.5,0.6)=0.6X\cap Y:\min(0.5,0.6)=0.5\neg X\cup\neg Y:\max(0.5,0.4)=0.5\neg X\cap\neg Y:\min(0.5,0.4)=0.4Element c5
\neg X:1-0.7=0.3\qquad\neg Y:1-0.2=0.8X\cup Y:\max(0.7,0.2)=0.7X\cap Y:\min(0.7,0.2)=0.2\neg X\cup\neg Y:\max(0.3,0.8)=0.8\neg X\cap\neg Y:\min(0.3,0.8)=0.3