Intelligent Systems II · TEE · read

Triangular membership: choose the side, then calculate

2. Fuzzy logic, from meaning to full solutions

Definitions → membership graphs → operations → rules → defuzzification → complete controller.

Why the triangle has two different fractions

Tri(2,5,8) means membership starts at zero at x=2, rises to 1 at x=5, then falls to zero at x=8. The first three numbers are input positions, not three membership degrees.

Where is x?MeaningCalculation
x≤2 or x≥8Outside, or at a zero-height endpoint0
2<x<5Part-way up the rising edge(x−2)/(5−2)
x=5At the peak1
5<x<8Part-way down the falling edge(8−x)/(8−5)

For x=3: distance travelled is 3−2=1; total rising width is 5−2=3; the height is 1÷3. For x=7: distance still remaining is 8−7=1; total falling width is 8−5=3; again the height is 1÷3. Use the branch containing the input before doing any division.

Yaad rakho: a = start, b = peak, c = end. x kahan pada hai, wahi fraction decide karega.

A graph is a rule for assigning membership

The horizontal axis gives the input x. The vertical axis gives membership μ. To read μ at an input, go vertically up from that x to the line, then horizontally to the membership axis.

A triangle has three parameters: a is the left zero, b is the peak with membership 1, and c is the right zero. We assume a < b < c.

Swipe across the diagram to read its labels ↔
Rising side: use distance from the left end. Falling side: use distance from the right end.
Diagram: Rising side: use distance from the left end. Falling side: use distance from the right end.. Labels: Triangle: left end 2, peak 5, right end 8 | 0 | 0.5 | 1 | 0 | 2 | 3 | 5 | 7 | 8 | 10 | μ | Input x | A | x = 3 | x = 7
Rising side: use distance from the left end. Falling side: use distance from the right end.
\mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}LaTeX: \mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}

Why the two fractions have these forms

On the rising side, x − a is how far you have climbed across the horizontal base; b − a is the full rising width. Their ratio goes from 0 to 1. On the falling side, c − x is the remaining horizontal distance to the right zero; c − b is the full falling width. That ratio goes from 1 to 0.

A fuzzy set A has triangular membership Tri(2, 5, 8). Find membership at x = 3. [2 marks · Practice]

Given

Left endpoint a = 2; peak b = 5; right endpoint c = 8; input x = 3.

To find

The membership degree μA(x), a number from 0 to 1.

Formula and why it applies

Locate x relative to a, b, c before choosing the branch.

\mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}LaTeX: \mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}

Solution

Step 1. Locate the input

2 < 3 ≤ 5, so membership increases as x moves toward the peak.

Step 2. Choose the correct expression

Rising side

\mu_A(3)=\frac{3-2}{5-2}=\frac{1}{3}=0.333333333LaTeX: \mu_A(3)=\frac{3-2}{5-2}=\frac{1}{3}=0.333333333
Step 3. Interpret the value

The degree of belonging to A is 0.333333333. It is a membership degree, not a probability.

Final answer. μA(3) = 0.333333333.

A fuzzy set A has triangular membership Tri(2, 5, 8). Find membership at x = 7. [2 marks · Practice]

Given

Left endpoint a = 2; peak b = 5; right endpoint c = 8; input x = 7.

To find

The membership degree μA(x), a number from 0 to 1.

Formula and why it applies

Locate x relative to a, b, c before choosing the branch.

\mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}LaTeX: \mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}

Solution

Step 1. Locate the input

5 < 7 < 8, so membership decreases as x moves away from the peak.

Step 2. Choose the correct expression

Falling side

\mu_A(7)=\frac{8-7}{8-5}=\frac{1}{3}=0.333333333LaTeX: \mu_A(7)=\frac{8-7}{8-5}=\frac{1}{3}=0.333333333
Step 3. Interpret the value

The degree of belonging to A is 0.333333333. It is a membership degree, not a probability.

Final answer. μA(7) = 0.333333333.

A fuzzy set A has triangular membership Tri(2, 5, 8). Find membership at x = 5. [2 marks · Practice]

Given

Left endpoint a = 2; peak b = 5; right endpoint c = 8; input x = 5.

To find

The membership degree μA(x), a number from 0 to 1.

Formula and why it applies

Locate x relative to a, b, c before choosing the branch.

\mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}LaTeX: \mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}

Solution

Step 1. Locate the input

2 < 5 ≤ 5, so membership increases as x moves toward the peak.

Step 2. Choose the correct expression

Rising side

\mu_A(5)=\frac{5-2}{5-2}=\frac{3}{3}=1LaTeX: \mu_A(5)=\frac{5-2}{5-2}=\frac{3}{3}=1
Step 3. Interpret the value

The degree of belonging to A is 1. This is full membership at the peak.

Final answer. μA(5) = 1.

A fuzzy set A has triangular membership Tri(2, 5, 8). Find membership at x = 9. [2 marks · Practice]

Given

Left endpoint a = 2; peak b = 5; right endpoint c = 8; input x = 9.

To find

The membership degree μA(x), a number from 0 to 1.

Formula and why it applies

Locate x relative to a, b, c before choosing the branch.

\mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}LaTeX: \mu_A(x)=\begin{cases}0,&x\le a\text{ or }x\ge c\\\dfrac{x-a}{b-a},&a<x\le b\\\dfrac{c-x}{c-b},&b<x<c\end{cases}

Solution

Step 1. Locate the input

9 is outside the open support (2, 8) or at an endpoint.

Step 2. Choose the correct expression

Outside the triangle

\mu_A(9)=0LaTeX: \mu_A(9)=0
Step 3. Interpret the value

The degree of belonging to A is 0. It is a membership degree, not a probability.

Final answer. μA(9) = 0.

Yaad rakho: Peak se left: x − a. Peak se right: c − x. Neeche usi side ki poori width.